Question

what weight of calcium oxide will be formed on heating 19.3 g of calcium carbonate​

Answer 1

Answer:

Cao 10.80 gm by the help of mile concept

Answer 2

Answer: 10.8 grams

Explanation:

$CaCO_3\rightarrow CaO+CO_2$

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

$\text{Number of moles of calcium carbonate}=\frac{19.3g}{100g/mol}=0.193 moles$

According to stoichiometry:

1 mole of $CaCO_3$ gives 1 mole of $CaO$

Thus 0.193 moles of $CaCO_3$ will give $CaO$=$\frac{1}{1}\times 0.193=0.193moles$ of $CaO$

Thus mass of $Cao$ produced= $moles\times {\text{Molar mass}}=0.193\times 56=10.8g$

Therefore, the weight of calcium oxide will be formed on heating 19.3 g of calcium carbonate​ is 10.8 grams