Chemistry, asked by vaishnavi1658, 10 months ago

what weight of calcium oxide will be formed on heating 19.3 gram of calcium carbonate

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Answered by claryjune415141

Answer:

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Explanation:

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Answered by ShivajiMaharaj45

Answer:

Explanation:

$\sf The\:reaction \:can\:be\:written\:as$

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$\sf CaCO_{3} \overset{\Delta}{\longrightarrow} CaO + CO_{2}$

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$\sf From\:reaction\:we\:understand \:that \:$

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$\sf 1\:mole\:of\:CaCO_{3} \:gives \:1\:mole\:of\:CaO$

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$\sf i.e 100\:gm\:of\:CaCO_{3}\:gives\:56\:gm\:of\:CaO$

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$\sf \therefore CaO \:produced\:by\:19.3\:gm\:of\:CaCO_{3}\:$

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$\sf = \frac {56 × 19.8}{100}$

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$\sf = 10.808$

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$\boxed{\bold {\sf Weight\:of\:CaO\:produced\:is\:10.808\:gm}}$

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