Question

What weight of CH4 should be taken which contains 2.4*10^24 atoms of H?

Answer 1

Answer:

yeh lo bhai answer hai

Explanation:

The statement must be as ‘2.4*10^-23’ atoms of hydrogen.

1 mole CH4 weighs=16 g

% of H2 in CH4=4/16*100=25%

1 mole of H2 weighs=2 g

6.022*10^23 atoms of H2 weigh=2 g

1 atom of H2 weighs=2/6.022*10^23

2.4*10^-23 of H2 weigh=2/6.022*10^23*(2.4*10^-23)=0.80 g

Therefore 25% of weight of CH4=0.80

1/4 of weight=4/5

Weight=4/5*4=3.2

Answer 2

Answer:

4 atoms of hydrogen (H) are present in 16g of methane (CH4) {Molecular Mass}

Explanation:

2.4*10^24 are contained in

= 16/4×2.4×10^24 g CH4

= 9.6×10^24 g

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