Question

what weight of CO is required to form re2(CO)10 from 2.50 g of Re2O7 according to the unbalanced equation

Answer 1

According to unbalanced reaction we have,

Re2O7  +  CO  -> Re2(CO)10 + CO2  

Let us balance it as : 

Re2O7  + 17 CO  -> Re2(CO)10 + 7CO2  

 Here, atomic mass of  , Re = 186.2, C = 12 and O = 16

So, molar mass of Re2O7  = 186.2 x2 + 16 x7 =484.4 gm

Molar mass of CO = 12+ 16 = 28 gm

We see that 484.4 gm of Re2O7  require =  17 x 28 =476 gm CO to form Re2(CO)10 

Hence, 2.50 gm  of Re2O7 will require = 476/484.4 x 2.5 =2.45  gm of  CO 

Answer 2

Explanation:

What weight of CO is required to form Re2(CO)10 from 2.50 g of Re2O7 according to the unbalanced reaction: Re2O7 + CO → Re2(CO)10 + CO2 (Re = 186.2, C = 12 and O = 16)