Question

WHAT WEIGHT OF FESO4 (MO WT=152) WILL BE OXIDIZED BY 200 ML OF NORMAL KMNO4 SOLUTION IN ACID SOLUTION?

Answer 1

thanks for the update and the

Answer 2

Answer:

Explanation:

Mol.wt.=152g

No.of eq. = 200/1000×1= 0.2

(Kmno4)

0.2=moles×n factor

N factor of feso4= 2

Now, moles of feso4=0.2/2=0.1

Hence,moles=mass/molar mass

Mass=0.1×152

=15.2g