what weight of H2So4 would be needed to make 750ml of 2 MOLAR Solution
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2 M= (mole of H2SO4 / molecular wt of H2SO4)/volume of soln
Mole= given wt/mol wt
Let us take given wt as x
So, mole= x/ 98
Volume =750 /1000
So molarity ie , 2= {(x/98)/(750/1000)}
=(x/98)/(3/4)
Gives x= 147 gm
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