Chemistry, asked by sparksha1725, 1 year ago

What weight of hcl is present in 155 ml of 0.5 molar solution?

Answers

Answered by dattahari09

3

molarity = moles /volume x1000

0.5 =n /155 x1000

0.5x155 /1000 =n

moles of hcl =0.0775

weight of HCL =

moles X molecular mass

weight = 0.0775 x36.5=2.828 gm

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