Question

what weight of K2Cr2O7 is required to prepare 250ml (N/10) solution?​

Answer 1

Answer:

It is nice question

Explanation:

Normality =

vol. of solution in L

No. of gm-eq of solute

we have,

gm-eq wt.=49.04,volum = 0.1L and N=0.05

now,

0.05=

0.1

No. of gm-eq of solute

No. of gm-eq of solute=0.005

0.005=

eq. wt

wt. of solute

wt. of solute=0.005×49.04

=0.2452 g

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