What weight of kcl that must be added to 1 kg of water so that the freezing point is reduced to 2k assume that kcl is 100% ionized in solution?
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i=2
WA=1kg
=1000g
ΔTf=2K
Kf=1.86KKgmol−1
MB=74.5g/mol−1
Substituting these value in the expression
WB=ΔTf×MB×WAi×kf×1000
=2×74.5×10002×1.86×1000
=40.05moles
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