Question

What weight of KMnO4 will be required to prepare 1250 ml of N/80 solution if eq. wt of KMNO4 is 94.8......??​

Answer 1

Answer:

11.85 g

Explanation:

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Answer 2

ANSWER

Definition:

• Molarity is a measure of the concentration of a solute in a solution or of any chemical species, in terms of amount of a substance in a given volume. A commonly used unit for molar concentration used in chemistry is mol/L. A solution of concentration 1 mol/L is also denoted as 1 molar (1 M).

• Molar concentration or molarity is most commonly expressed in units of moles of solute per litre of solution. For use in broader applications, it is defined as amount of solute per unit volume of solution, or per unit volume available for the species, represented by lowercase c:

• c= Vn

where,

n= no. of moles of solute.

V= volume of solution in litres.

Calculation:

Let the weight required be x g.

Molarity c=0.1 M

Number of moles of KMnO4 is n= 158.03x moles

The volume of solution in litrs is V= 250/1000 =0.25 litres

Molarity of the given solution is given as c= Vn

c= 158.034x0.25=0.1

⟹x=158.034×0.1×0.25

⟹x=3.95 g

Therefore, weight of KMnO4 required is 3.95 g.