Question

What weight of methane should be taken which contains 2.4*10^24 atoms of hydrogen?

Answer 1

4 atoms of hydrogen are present in 16 g of methane(molar mass)

hence,2. 4×10^24 atoms are contained in =16/4×2.4×10^24 g CH4

=9.6×10^24 g

..........

Answer 2

Answer:

16 grams of methane should be taken which contains 2.4×10²⁴ atoms of hydrogen.

Explanation:

• Methane is formulated as CH₄. From the formula, we can see that there are four atoms of hydrogen in one molecule of methane.
• Now, the number of molecules of CH₄ in 2.4×10²⁴ atoms of hydrogen is,

                                            $\frac{2.4\times 10^{24}}{4}=6\times 10^{23}$       (1)

• Now the number of moles of CH₄ is calculated as,    

                                             $\mathrm{n=\frac{N}{N_{a}} }$                      (2)

Where,

n=number of moles of methane      

N=number of molecules of methane      

$\mathrm{N_{a}}$=avagaro number=6×10²³

Inserting the values in equation (2) we get;

                              $\mathrm{n=\frac{6\times 10^{23}}{6\times 10^{23}}}$

                                 $\mathrm{n=1}$                        (3)

The number of moles can also be calculated as,

                              $\mathrm{n=\frac{m}{M} }$            (4)

m=mass of the given substance

M=molar mass of the given compound

The molar mass of methane(M)=16 gram

By inserting the value of "n" and "M" in equation (4) we get;

                                       $\mathrm{1=\frac{m}{16} }$

                              $\mathrm{m=16\times 1=16 \ grams}$

So, 16 grams of methane should be taken which contains 2.4×10²⁴ atoms of hydrogen.

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