Question

what weight of Mg and sulphuric acid would be required to produce enough hydrogen at NTP to reduce completely 15 gm of copper oxide to copper​

Answer 1

Answer:

Reaction of zinc to produce hydrogen-

Zn+2HCl⟶ZnCl

2

+H

2

Reaction of hydrogen to reduce copper oxide into copper-

CuO+H

2

⟶H

2

O+Cu

From the above reactions-

1 moles of Zn produces 1 mole of hydrogen gas and 1 mole of hydrogen required to reduce 1 mole of CuO.

Mole of CuO reduced = mole of Zn required

Therefore,

No. of moles of CuO reduced =

molar mass of CuO

moles of CuO

Given weight of CuO=8.5g

Molecular weight of CuO=79.5g

Therefore,

No. of moles of CuO reduced =

79.5

8.5

=0.107 mol

Therefore,

No. of moles of Zn required =0.107 mol

Now,

Molecular weight of Zn=65.4g

∴ Weight of Zn required =0.107×65.4=6.99g

Hence 6.99g of Zn will be required

Explanation:

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