Question

What weight of N2 is present in a 22.4 lit flask at 273 c and 380 mm

Answer 1

Answer:

iven,

At, NTP (293 K, 76 cm Hg): Volume,V=22.4L ,Number of mole, n

1

=1mole

273

o

C=546K

At (38 cm, 546 K): Volume V=5.6L

From ideal gas equation.

PV=nRT

P

1

V

2

P

1

V

1

=

n

2

RT

2

n

1

RT

1

⇒

38×5.6

76×22.4

=

n

2

R×546

1×R×293

⇒n

2

=0.67mole

1moleN

2

=28g

0.067moleN

2

=28×0.067=1.87g

Hence, mass of nitrogen is 1.87g

hope it helps very much