What weight of Nacl would be decomposed
by 4.9 g of sulphuric acid, if 6g of NaHso4
and
1.825 g of HCL were produced in the
reaction
acording to low of conservation of
mass.
Answers
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1
Answer:
NaCl + H2SO4 → NaHSO + HCl
Given Mass: x 4.9 g 6 g 1.825 g
Molecular weight: 58.5 g 98 g 120 g 36.5 g
Moles: x/58.5 0.05 0.05 0.05
Therefore, 0.05 moles of reactant are reacting produce 0.05 moles of each of the product.
Therefore, Amount of NaCl consumed:
x/ 58.5 =0.05
x=2.925 g
Explanation:
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