Question

What weight of Nacl would be decomposed
by 4.9 g of sulphuric acid, if 6g of NaHso4
and
1.825 g of HCL were produced in the
reaction
acording to low of conservation of
mass.​

Answer 1

Answer:

 NaCl + H2SO4 → NaHSO  + HCl

Given Mass:              x              4.9 g             6 g            1.825 g

Molecular weight: 58.5 g         98 g            120 g           36.5 g

Moles:                      x/58.5    0.05             0.05             0.05

Therefore, 0.05 moles of reactant are reacting produce 0.05 moles of each of the product.  

Therefore, Amount of NaCl consumed:  

x/ 58.5 =0.05

x=2.925 g

Explanation: