Question

What weight of sodium chloride is decomposed by 4.9 g of sulphuric acid, if 6g of sodium hydrogen sulphate and 1.825 g of hydrogen chloride are produced in the same reaction?

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Answer 1

Hello!

Here is your answer

NaCl + H2SO4 = NaHSO4 +HCl

( x g) (4.9g) (6 g) (1.825 g)

By Law of Conservation of mass,

Mass of reactants = Mass of products

xg + 4.9g = 6g + 1.825g

xg + 4.9g = 7.825g

xg = 7.825g - 4.9g

xg = 2.725 g

Answer 2

According to the statement :

The decomposition reaction of Sodium chloride (done by sulphuric acid) took place. Here 6 g of Sodium Hydrogen Sulphate is produced and 1.825 g of Hydrogen Chloride is produced.

Then ,

We have to find the weight of sodium chloride which reacted with sulphuric acid is to be found.

The concept to be used :

Conservation of Mass : That is the mass of the products is as same as the mass of reactants.

NaCl + H2SO4 → NaHSO4 + HCl

Let the amount of NaCl be x.

Then ,

x + 4.9 g = 6 g + 1.825 g

x = 6 g + 1.825 -4.9 g

x = 2.725 g .

The amount of NaCl , to be found is 2.725 g.