Question

What weight of solute required to prepare 100m.l of 0.1N of NaOH solution

Answer 1

Answer:

     w = 0.4g

Explanation:

eq mass of NaOH = 40

Normality(N) = n-g eq of solute / Volume of solution (in L)

N = weight of solute × 1000 / eq mass of solute × Volume of solution (in mL)

0.1 = w × 1000 / 40 × 100

w = 0.1 × 40 / 10

w = 0.1 × 4

w = 0.4g

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