Question

what weight of zinc would be required to produce enough hydrogen to reduce 8.5g of cuo

Answer 1

First see the reactions :-
step 1 :- Zinc reacts with hydrochloride and produce hydrogen gas :
Zn + 2HCl ----> ZnCl₂ + H₂
step 2 :- now, hydrogen reacts with CuO to produce copper :
CuO + H₂ -----> Cu + H₂O

Here it is clear that one of Zn produce 1 mole of hydrogen gas and one mole of hydrogen require to produce 1 mole of Cu.
∴ mole of CuO = mole of Zn
⇒given weight of CuO/molecular weight = weight/atomic weight
⇒8.5g/(63.5 + 16) = weight/65
⇒8.5/79.5 × 65 = weight
⇒weight = 8.5 × 65/79.5 = 6.9 g

Hence , zinc would be required = 6.9g

Answer 2

Answer:

6.09

Explanation:

First see the reactions :-

step 1 :- Zinc reacts with hydrochloride and produce hydrogen gas :

Zn + 2HCl ----> ZnCl₂ + H₂

step 2 :- now, hydrogen reacts with CuO to produce copper :

CuO + H₂ -----> Cu + H₂O

Here it is clear that one of Zn produce 1 mole of hydrogen gas and one mole of hydrogen require to produce 1 mole of Cu.

∴ mole of CuO = mole of Zn

⇒given weight of CuO/molecular weight = weight/atomic weight

⇒8.5g/(63.5 + 16) = weight/65

⇒8.5/79.5 × 65 = weight

⇒weight = 8.5 × 65/79.5 = 6.9 g

Hence , zinc would be required = 6.9g