Question

what what will be the stopping distance if the initial velocity is doubled??
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Answer 1

We know from third equation of motion that s(distance) is directly proportional to u^2. Thus, if the speed is doubled then then the stopping distance becomes 4 times the given value. so, we can see as, speed is doubled, the braking distance goes increases by 4 times .

Answer 2

Answer:

As given that

Initial velocity is doubled

let initial velocity u = 2

then u is doubled ===> 2 × 2 ===> 4

So , the stopping distance will be

increase "4" ( Four ) times because the

initial velocity is doubled .

Explanation:

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