Question

what will a loan of rs 15000 amount to in 3 years if compounded annually at rate of 10%p.a.
show me the full method

Answer 1

SUBJECT .

MATH



TOPIC


INTEREST( Compound interest)



QUESTION.



what will a loan of rs 15000 amount to in 3 years if compounded annually at rate of 10%p.a.
show me the full method



ANSWER.



GIVEN.

P=15000 Rs


Time=3year


R=10% p.a


FORMULA USED



$a =p( {1 + \frac{r}{100} })^{t}$


C.I= A-P




STEP 1



$a = 15000( {1 + \frac{10}{100} )}^{3}$



$a = 15000( { \frac{100 + 10}{100}) }^{3}$




$a = 15000 \times \ \frac{110}{100} \times \frac{110}{100} \times \frac{110}{100}$




$a = 15 \times 11 \times 11 \times 11$



$a = 19965 \: rs$

C.I = A-P= 19965-15000



= 4965 Rs




AMOUNT AFTER INTEREST IS = 19965 RS

Answer 2

$\huge\bold\red{Solution :\longrightarrow}$

Given,

Principal (P) = Rs 15000

Time (T) = 3 years

Rate (R) = 10% p.a.

Since compounded annually

$\mathsf{Amount = P \times (1 + \frac{R}{100} ) {}^{T} }\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathsf{= Rs} \: \: \mathfrak{15000 \times (1 + \frac{10}{100} ) {}^{3} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathsf{= Rs }\: \:\mathfrak{ 15000 \times \frac{110}{100} \times \frac{110}{100} \times \frac{110}{100}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathsf{= Rs} \: \: \mathfrak{19965} \: \: \: \boxed{\boxed{\boxed{\bold{\green{Ans}}}}}$

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