Question

What will be amount of DNA in products of meiosis II, if amount of DNA in meiocyte was 40 pg at G1 phase?

(a) 10 pg

(b) 20 pg

(c) 40 pg

(d) 5 pg​

Answer 1

Answer:

Explanation: In the first phase of the meiosis if the meiocyte contains 30pg DNA then it will be doubled in the first phase and then it will be 60pg DNA after phase. When it enters the second meiosis II then it will be divided into 4 daughter cells then 60/4=15 pg.

Answer 2

Answer:

(b) 20 pg

Explanation:

After the G1 phase, the DNA content would get doubled in the S phase, as a result of which 40pg DNA would become 80 pg of DNA. After meiosis I, the DNA content would get halved to give 40pg of DNA and after meiosis II the DNA content would further decrease by a factor of 2 to produce meiocytes with 20 pg of DNA. This is equational division having same number of chromosomes but reduced DNA content.

So the correct option is b - '20 pg '.