Question

What will be answer of :

Tan41/cos49

Answer 1

$\sf\dfrac{tan 41°}{cos 49°}$

= $\sf\dfrac{tan (90-49)°}{cos 49°}$

= $\sf\dfrac{cot 49°}{cos 49°}$

= (cos 49°/sin49°)/cos 49°

= $\bold{\dfrac{1}{sin 49°}}$

Hope Helps uh..! :)

Answer 2

Answer:

Step-by-step explanation:

���41°���49°cos49°tan41°

= ���(90−49)°���49°cos49°tan(90−49)°

= ���49°���49°cos49°cot49°

= (cos 49°/sin49°)/cos 49°

= 1/sin49°

Hope Helps uh..! :)