what will be concentration in ppb and ppm of 0.1M cu (N03)2 solution
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PPM = 2 * 10^4
PPB = 2 * 10^7
Explanation:
Given: 0.1M Cu(N03)2 solution.
Find: PPB and PPM.
Solution:
Molar mass of Cu(NO3)2 = 64 + 2*14 + 16*6 = 64 + 28 + 96 = 188 g/mol
So 0.1 M Cu(NO3)2 will be 18.8 g/L.
Ppm is the same as mg/kg solution and at 1 significant figure.
Density of water = 1 kg/L.
So 188 g/L = 18.8 * 1000 mg/kg. That is 18800 ppm. 1 significant figure.
Therefore, 2 * 10^4 ppm or 2 * 10^7 ppb.
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