What will be current drawn by an electric bulb of 40 w when it is connecting to a source of 220 v ??
plzzz plzzz solve.
Answers
Answered by
3
hey!!
your answer is ------
Given ,
power P = 40w &
potential difference V = 220volt
therefore , by formula
P = VI
=> I = P/V
=> I = 40/220 = 0.18 ≈ 0.2ampere
hope it helps you
your answer is ------
Given ,
power P = 40w &
potential difference V = 220volt
therefore , by formula
P = VI
=> I = P/V
=> I = 40/220 = 0.18 ≈ 0.2ampere
hope it helps you
Answered by
4
Solution is given above attachment .
Hope it's helps you.
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Hope it's helps you.
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