Question

WHAT WILL BE DE BROGLIE (MEASIRED IN UNIT OF M) FOR AN OBJECT OF MASS 2KG MOVING AT 50 M/S?

Answer 1

We have the formula for de-Broglie wavelength associated with a moving material particle as λ = $\frac{h}{mv}$

Here, m = 2 kg
v = 50 m/s
h = Planck's constant = 6.626 * $10^{-34}$ Js

Substituting these values, we get
λ = $\frac{6.626 * 10^{-34}}{2 * 50}$

λ = $\frac{6.626 * 10^{-34}}{100}$

λ = $6.626 * 10^{-34} * 10^{-2}$

λ = $6.626 * 10^{-36}$ m

Hence, the de-Broglie wavelength will be  $6.626 * 10^{-36}$ m