Question

What will be Digit in blank space of 142_315 so that the number is divisible by 11?​

Answer 1

Answer:

$545794561230. = \sqrt{ \sqrt[ \frac{ { { {y(x | < > \div \times - + > > < \leqslant \geqslant | }^{?} }^{2} }^{2} }{3 = \sqrt[ \sqrt[ \sqrt{ \sqrt{ \sqrt{ \sqrt{?} } } } ]{?} ]{?} } \times \frac{?}{?} ]{?} }$

Answer 2

Answer:

please mark as brainlist

Step-by-step explanation:

Sum of odd digits = 9 + (blank space) + 8 = 17 + blank space

Sum of even digits = 2 + 3 + 9 = 14

As we know,

The number is divisible by 11 if the difference between the sum of the digits at odd places and the sum of the digits at even places is divisible by 11.

If we make the sum of odd digits = 25

then we will have difference = 25 - 14 = 11

which is divisible by 11.

To make the sum of odd digits = 25,

the number at black space would be 8.

(b) 8 __ 9484

Sum of odd digits = 8 + 9 + 8 = 25

Sum of even digits = blank space + 4 + 4 = blank space + 8

The number is divisible by 11 if the difference between the sum of the digits at odd places and the sum of the digits at even places is divisible by 11.

If we make the sum of even digits = 14 then we will have difference = 25 - 14 = 11 which is divisible by 11.

To make the sum of even digits = 14,

the number at black space would be 6.

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