What will be distance covered by vehicle after applying brakes with retardation 8 m/s
2
if its
velocity is 72 km/h ?
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Answer:
324m
Explanation:
Appling v^2=u^2+2as
0^2 = (72)^2 + 2*-8s
0 = 5184 - 16s
s = - 5184/-16
s = 324m
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