Question

What will be distance travelled by a body before coming to rest if it is moving with a speed of 10 metre per second and the coefficient of friction between the ground and body is 4​

Answer 1

Explanation:

The friction force is Fp = μFn where Fn is the normal force, Fn = mg in this case.

So Fp = 0.45mg but in general, F = ma so 0.45mg = ma or a = 0.45g

So a = -0.45(9.81) = -4.4145 (a is negative as a retarding acceleration)

From v^2 = u^2 + 2as, we find 0 = 15^2 – 2(4.4145)s

So s = 225/8.829 = 25.48m

The body slides for 25.48m before coming to rest.