Question

What will be energy stored in capacitor of capacity 2F and potential 2 volt​

Answer 1

Answer:

The energy stored in a capacitor can be expressed in three ways: Ecap=QV2=CV22=Q22C E cap = QV 2 = CV 2 2 = Q 2 2 C , where Q is the charge, V is the voltage, and C is the capacitance of the capacitor. The energy is in joules when the charge is in coulombs, voltage is in volts, and capacitance is in farads.

Explanation:

wkakakakak

Answer 2

Given:

Capacitor of 2F is connected to 2 volts .

To find:

Energy stored ?

Calculation:

The general expression of energy stored in a capacitor is given as:

$E = \dfrac{1}{2} \times C{V}^{2}$

• 'C' is capacitance and 'V' is potential difference across capacitor.

$\implies E = \dfrac{1}{2} \times 2 \times {2}^{2}$

$\implies E = \dfrac{1}{2} \times 2 \times 4$

$\implies E = 4 \: joule$

So, energy stored in capacitor is 4 Joules