Question

What will be energy used by the battery if the battery has to drive 6.28 x 1018 electrons with potential difference of 20 v across the terminal ?

Answer 1

Answer : The energy used by the battery will be, 20.096 J

Solution :

First we have to calculate the charge of electrons.

As, 1 electron has $1.6\times 10^{-19}C$ charge

So, $6.28\times 10^{18}$ electrons has $(6.028\times 10^{18})\times (1.6\times 10^{-19}C)=1.0048C$ charge

Now we have to calculate the energy used by the battery.

Formula used :

$E=Q\times V$

where,

E = energy

Q = charge

V = potential difference

Now put all the given values in this formula, we get the energy used by the battery.

$E=(1.0048C)\times (20V)=20.096J$

Therefore, the energy used by the battery will be, 20.096 J