Question

what will be intensity of electric field at a distance of 3 m from 6 micro coulamb charge​

Answer 1

Answer:

According to Coulomb's law we can define electrical force between two charge:

F=kqQsourcer2F=kqQsourcer2

Where k is permittivity of medium. For space k=8.85×10−12Nm2C−2k=8.85×10−12Nm2C−2

An electric field is a vector field that associates to each point in space the Coulomb force that would be experienced per unit of electric charge, by an source charge at that point.

So Electric Field,

E=Fq=kQsourcer2E=Fq=kQsourcer2

Here,

Q=1CQ=1C and r=1mr=1m

E=8.85×10−12NC−1

Explanation:

According to Coulomb's law we can define electrical force between two charge:

F=kqQsourcer2F=kqQsourcer2

Where k is permittivity of medium. For space k=8.85×10−12Nm2C−2k=8.85×10−12Nm2C−2

An electric field is a vector field that associates to each point in space the Coulomb force that would be experienced per unit of electric charge, by an source charge at that point.

So Electric Field,

E=Fq=kQsourcer2E=Fq=kQsourcer2

Here,

Q=1CQ=1C and r=1mr=1m

E=8.85×10−12NC−1