What will be maximum no. of electrons in an orbital with, n= 3, l = 2, n= –2?[1]
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First of all the question is not properly asked,as principal quantum no(n) can't be 0 or negative.
If you are asking for the answer to the following question
What will be maximum no. of electrons in an orbital with, n= 3, l = 2, m= –2?
Then answer is only 2.
For n=3, l can vary from 0 to 2. l=2 indicate d subshell. Now for d subshell value of m can vary from -2 to +2. Each value of m indicates a orbital.
So the combination is possible just once i.e.
n= 3, l = 2, m= –2 combination indicate a orbital.
As each orbital contain 2 electrons, so this orbital with such combination contain 2 electrons.
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