what will be obtain if 4a-7ab + 3b+12 is subtracted from 12a- 9ab+5b-3
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Answer:
subtract 4a−7ab+3b+12 from 12a−9ab+5b−3
=12a−9ab+5b−3−(4a−7ab+3b+12)
=12a−9ab+5b−3−4a+7ab−3b−12
=8a−2ab+2b−15
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Answered by
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Answer:
12a-9ab+5b-3 - (4a-7ab+3b+12)
12a-9ab+5b-3-4a+7ab-3b-12
8@-2ab+2b-15
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