What will be pH of solution of Mg(oH) having 10^-3 concentrations
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1
Answer:
When Mg(OH)
2
starts precipitation, then
[Mg
2+
][OH
⊝
]
2
=K
sp
of Mg(OH)
2
[0.1][OH
⊝
]
2
=1×10
−11
∴[OH
⊝
]=10
−5
M∴pOH=5
∴pH=14−pOH
pH=14−5=9
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