Question

What will be radius of base of a cone whose height is 6 m and slant height is 10 m? ​

Answer 1

Answer:

slant height of the cone (l)= 10m

height of the cone (h) = 6m

$l {}^{2} = r {}^{2} + h {}^{2}$

${r}^{2}= l {}^{2} - h {}^{2}$

${r}= \sqrt{10 {}^{2} - 6 {}^{2} }$

$r = \sqrt{100 - 36}$

$r = \sqrt{64}$

$r = 8m$

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