Question

What will be remainder when 17^200 is divided by 18 ?

Answer 1

[x^n - a^n] is completely divisible by [x+a] (when n is even0

so, 17^200 - 1^200 is completely divisible by 17+1 i.e 18

17^200 -1 is completely divisible by 18

Hence we get 1 as remainder on dividing b/s by 18

Answer 2

Answer:

The remainder obtained when 17^200 is divided by 18 is 1.

Step-by-step explanation:

As per the question,

We need to find the remainder obtained when 17^200 is divided by 18.

As we know,

• There is a formula that $(x^{n} -a^{n} )$ is completely divisible by $(x+a)$.
• So, after applying the same formula here:

Let x = 17 and a=1

So,

$17^{200} - 1^{200}$ is completely divisible by 17+1 =18

So, when we divide $17^{200}$ by  18, the reminder left will be $1^{200} = 1$

Hence,

The remainder obtained when 17^200 is divided by 18 is 1.

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