what will be sn for this geometric progression
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aₓ=a₁rˣ⁻¹
sₓ=a₁+a₂+....aₓ
sₓ=a₁(rˣ-1)/(r-1)
a₁=3
r=4
sₓ=3(4ˣ-1)/3
in a way answer is c
s₁=a₁=3
sₓ=a₁+a₂+....aₓ
sₓ=a₁(rˣ-1)/(r-1)
a₁=3
r=4
sₓ=3(4ˣ-1)/3
in a way answer is c
s₁=a₁=3
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