Question

what will be the 127th term of the A. P 108,100,92,84
plzzz answer me urgently guys
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Answer 1

Answer:

First term (a) = 108 ...............(i)

Common difference (d) = t2 -t1

= 100 - 108

= -8 ..............(ii)

We know,

nth term = a +(n-1)d

Therefore;

127th term = 108 + (127-1)(-8) [From (i) and (ii)]

= 108 + 126×(-8)

= 108 - 1008

= -900

Hence the 127th term of the AP is : -900

Answer 2

-900

Step-by-step explanation:

formula=an=a+(n-1)d

d=a2_a1

100-108=-8

an=108+(127-1)-8

=108+(126)-8

=108+(-1008)

=108-1008

=-900