Question

what will be the 12th term of an AP 5,8,11,14

Answer 1

given 5,8,11,14... are in AP

first term = a =5

common difference = d= a2-a1 =8-5 =3

nth term =an = a+(n-1)d
here a=5, d= 3,n= 12

a12 = 5+(12-1)3

= 5+11*3
=5+33
=38
12th term in AP = 38

Answer 2

a12 = a + (n-1)d
         = 5 + (12-1)3
         = 5 + 33
         =38