What will be the accelaration of an elevator of weight 3000kg. When the tension in the supporting cable is 3300 n? (take g =9.8m/s^2)?
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weight(mg)=3000×9.8 N
tension=3300N
Mass(m)=3000Kg
let acceleration be =a
T-mg=ma
3300-3000×9.8=3000a
100(33-30×9.8)=100×10a
33-294=10a
-261=10a
a=-26.1m/s^2(downward acceleration)
tension=3300N
Mass(m)=3000Kg
let acceleration be =a
T-mg=ma
3300-3000×9.8=3000a
100(33-30×9.8)=100×10a
33-294=10a
-261=10a
a=-26.1m/s^2(downward acceleration)
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