Physics, asked by arunchoudhary125, 1 year ago

What will be the acceleration due to gravity whose mass is 8 times the mass of the earth and whoes radius is twice that of earth

Answers

Answered by ahmadammarlm10
1

f =  \frac{g \times m}{{r }^{2} }

if mass is octupled and radius doubled

f =  \frac{g \times 8m}{ {2r}^{2} }

Hence

f =  \frac{g \times m}{ {r}^{2} }  \times 4

This implies that the acceleration due to gravity would be 4 times of the acceleration of gravity on Earth

Hence the acceleration due to gravity would be

4 \times 9.8 \: ms {}^{ - 2}

39.2 \: ms {}^{ - 2}

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