what will be the altitude of triangle whose area is 72sq.m and base is 4m
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Answered by
1
Answer:
Step-by-step explanation:
Step-by-step explanation:
Area of triangle
1/2×base×height=72m
1/2×4×h=72m
h=72×2/4
h=36m
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Answered by
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Let the altitude of Δ=h m
Ar. of Δ=72 m² & base=4 m
As we know,Ar. of Δ=1/2 ×b×h
h=72÷2=36 m
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