Question

what will be the amount of glucose dissolved in it 10 ml to make its one molar solution?
a)1
b)1.8
c)200
d)900

Answer 1

Answer:

ans is b. 1.8

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Answer 2

Explanation:

Concentration Questions & Answers

✍ How many grams of glucose would be dissolved to make 1 liter of a 0.5M glucose solution?

0.5 mole/liter x 180 grams/mole x 1 liter = 90 g

✍ How many molecules of glucose are in that 1 liter of 0.5M glucose solution?

0.5 mole/liter x 1 liter x 6.023x1023 molecules/mole = 3.012x1023 molecules

✍ What is the concentration of the 0.5M glucose solution expressed in mM?

0.5 mole/liter x 1000 mmoles/mole = 500 mM

✍ What is the concentration of the 0.5M glucose solution expressed in %?

0.5 mole/liter x 180 grams/mole x 1 liter/1000ml = 0.09 g/ml = 9 g/100ml = 9%

✍ How many grams of sucrose would be dissolved in 1 liter of a 0.5M sucrose solution? How does that

compare to the grams of solute in the 0.5M glucose solution?

0.5 mole/liter x 342 grams/mole x 1 liter = 171 g = almost twice as many grams

✍ How many molecules of sucrose in that 1 liter of 0.5M sucrose solution? How does that compare to the

amount of solute in the 0.5M glucose solution?

0.5 mole/liter x 1 liter x 6.023x1023 molecules/mole = 3.012x1023 molecules = same

number of molecules

✍ How much of the 0.5M glucose solution is needed to provide 100 mg of glucose?

100 mg x 1 mole/180 grams x 1 gram/1000 mg x 1 liter/0.5 moles x 1000 ml/liter = 1.11 ml

✍ If you were to dilute 100 ml of the 0.5M glucose solution with 400 ml water, what would be the

concentration of the diluted solution?

C2=(V1 x C1)/(V2) = (100 ml x 0.5 M)/(500 ml) = 0.1 M

✍ If you were to dilute 10 µl of the 0.5M glucose solution with 1.99 ml water, what would be the

concentration of the diluted solution?

C2=(V1 x C1)/(V2) = [(10 µl x 0.5 M)/(2 ml)] x 1 ml/1000 µl = 0.0025 M = 2.5 mM

✍ How would you prepare 10 ml of 0.1M glucose from the 0.5M glucose solution?

V1=(V2 x C2)/(C1) = (10 ml x 0.1 M)/(0.5 M) = 2 ml 0.5 M glucose + 8 ml H2O

✍ How would you prepare 100 ml of 1% glucose from the 0.5M glucose solution?

C1 = 0.5 M = 9% glucose [from fourth question above]

V1=(V2 x C2)/(C1) = (100 ml x 1%)/(9%) = 11 ml 9% glucose + 89 ml H2O

✍ How would you prepare 20 µl of 25 mM glucose from the 0.5M glucose solution?

C1 = 0.5 M = 500 mM glucose [from third question above]

V1=(V2 x C2)/(C1) = (20 µl x 25 mM)/(500 mM) = 1 µl 500 mM glucose + 19 µl H2O

✍ How would you prepare 100 µl of 40 mM glucose/40 mM sucrose from the 0.5M glucose and 0.5M

sucrose solutions?

V1=(V2 x C2)/(C1) = (100 µl x 40 mM)/(500 mM) = 8 µl 500 mM glucose per 100µl final vol.

V1=(V2 x C2)/(C1) = (100 µl x 40 mM)/(500 mM) = 8 µl 500 mM sucrose per 100µl final vol.

Total final volume = 100µl = 8 µl 0.5 M glucose + 8 µl 0.5 M sucrose + 84 µl H2O

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