Physics, asked by saad5292, 4 months ago

What will be the amplitude of the resultant wave when two waves of same amplitude A, but with an initial phase difference of 30 degrees superimpose on each other?​

Answers

Answered by Anonymous
0

The equation of the two superimposing waves can be give by

y

1

=a

1

sin(ωt) and y

2

=a

2

sin(ωt+π/2)=a

2

cos(ωt).

So, the equation of the resultant wave is y=y

1

+y

2

=a

1

sin(ωt)+a

2

cos(ωt).

Assuming a

1

=acos(ϕ) and a

2

=asin(ϕ), we get

y=asin(ωt+ϕ).

Here a

1

2

+a

2

2

=a

2

(sin

2

(ϕ)+cos

2

(ϕ))=a

2

⇒a=

a

1

2

+a

2

2

.

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