What will be the amplitude of the resultant wave when two waves of same amplitude A, but with an initial phase difference of 30 degrees superimpose on each other?
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The equation of the two superimposing waves can be give by
y
1
=a
1
sin(ωt) and y
2
=a
2
sin(ωt+π/2)=a
2
cos(ωt).
So, the equation of the resultant wave is y=y
1
+y
2
=a
1
sin(ωt)+a
2
cos(ωt).
Assuming a
1
=acos(ϕ) and a
2
=asin(ϕ), we get
y=asin(ωt+ϕ).
Here a
1
2
+a
2
2
=a
2
(sin
2
(ϕ)+cos
2
(ϕ))=a
2
⇒a=
a
1
2
+a
2
2
.
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