Question

What will be the answer​

Answer 1

$\huge\bold{\gray{\sf{Answer:}}}$

$\bold{Explanation:}$

$\sf\implies\: \dfrac{n}{4} - 5 = \dfrac{n}{6} + \dfrac{1}{2}$

✹Taking like terms together :-

$\sf\implies\: \dfrac{n}{4} - \dfrac{n}{6} = \dfrac{1}{2} + 5$

$\sf\implies\: \dfrac{n \times 6 - n \times 4}{24} = \dfrac{1 + 5 \times 2}{2}$

$\sf\implies\: \dfrac{6n - 4n}{24} = \dfrac{1 + 10}{2}$

$\sf\implies\: \dfrac{2n}{24} = \dfrac{11}{2}$

$\sf\implies\: 4n = 264$

$\sf\implies\: n = \dfrac{264}{4} = 66$

$\huge\bold{\red{n = 66}}$

Check:

$\sf\implies\: \dfrac{66}{4} - 5 = \dfrac{66}{6} + \dfrac{1}{2}$

$\sf\implies\: \dfrac{33}{2} - 5 = 11 + \dfrac{1}{2}$

$\sf\implies\: \dfrac{33 - 10}{2} = \dfrac{22 + 1}{2}$

$\sf\implies\:\dfrac{23}{2} = \dfrac{23}{2}$

Answer 2

$\frac{n}{4}$-${5}$=$\frac{n}{6}$+$\frac{1}{2}$

Take the LCM Of denominators

$\frac{n-20}{4}$=$\frac{n+3}{6}$

By cross multiplication

${4(n+3)}$= ${n-20(6)}$

${4n + 12}$ = ${6n-120}$

Transpose the terms

${6n-4n=120+12}$

${2n=132}$

$\frac{132}{2}$=${n}$

${n=66}$