Question

what will be the answer ??​

Answer 1

Step-by-step explanation:

Let l=x→0limxsinxcoshx−cosx

Now, applying L'Hospital's rule, we get

l=x→0limxcosx+sinxsinhx+sinx

                                      [∵dxd(coshx)=sinhx]

Again, applying L'Hospital's rule, we get

l=x→0limx(−sinx)+cosx+cosxcoshx+cosx

                                      [∵dxd(sinhx)=coshx]

⇒l=x→0lim2cosx−xsinxcoshx+cosx=2cos(0)−0cosh(0)+cos(0)

  =21+1=1           [∵cosh(0)