What will be the answer of 1/root2+root3?
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--------Answer is √3-√2
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=1/√2+√3
=(1/√2+√3)×(√2-√3/√2-√3). (rationalize the denominator)
=√2-√3/(√2)^2-(√3)^2
=√2-√3/2-3
=√2-√3/-1
= -(√2-√3)/1
= -√2+√3/1
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