what will be the answer of above statement in KPA?
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1
Answer:
A→benzene,B→toluene
In 1:1 molar mixture of A and B
∴X
A
=
2
1
,X
B
=
2
1
P=P
A
o
X
A
+P
B
o
X
B
P=12.8×
2
1
+3.85×
2
1
=8.325 kPa
Y
A
=
P
P
A
o
X
A
=
8.325
12.8×
2
1
=0.768
⇒Y
B
=1−Y
A
=1.0.768=0.232
So the vapour will contain higher percentage of benzene.
Option A is correct.
Explanation:
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