Question

what will be the answer of this integration?

Answer 1

(Tan x + tan d)/tan x - tan d ×dx

Given, x-d=2

d =x-2

(Tan x + tan (x -2))/(tan x - tan(x-2) × x (x -2)

Tan(x + (x -2))/tan(x - (x-2)) × x² -2x

[Both tan is common .therefore it will be cancelled]

X+(x-2)/x-(x-2) × x²-2x. [Open the brackets]

[X+x-2]/[x-x+2] ×x²-2x

(2x-2)/2 ×(x²-2x)

2(x-1)/2 ×(x²-2x) [2 and 2 on numerator and denominator will be cancelled]

(X-1)(x²-2x)

1(x-1)+x(x-2)

X=-1 d=x-2=-1-2=-3

X=1 d=1-2=-1 or

X=2. d=2-2=0