What will be the answer please explain.
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we are given force ,so we can find acceleration by dividing it by mass.
a vector=Fvector/m=(3t^2i+4tj)/2=(3/2)t^2i + 2tj.
now to find the velocity we need to differentiate it.
v=(3/2)(2)ti +2j
v=3ti+2j
so velocity at t=2sec
v=3(2)I + 2j
v=(6i+2j)m/s
a vector=Fvector/m=(3t^2i+4tj)/2=(3/2)t^2i + 2tj.
now to find the velocity we need to differentiate it.
v=(3/2)(2)ti +2j
v=3ti+2j
so velocity at t=2sec
v=3(2)I + 2j
v=(6i+2j)m/s
Anonymous:
the option are not matching with answer.
may be some missprint.
in first option.
answer is third
4i + 4j
it is very unlikely that there would be any mistake
i did it by different method, the answer is same.
okay
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