What will be the answer to question from the options ?
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answer will be c part
as if you put the value of x in f(x)
then in the bracket you will get
1+x^2+2x/1+x^2-2x
as both numerator and denominator form the formula of (a+b)^2 & (a-b)^2
therefore it will be
log{(1+x)^2/(1-x)^2}
log{1+x/1-x}^2
as it is the property of log that the power comes down therefore it will be equal to
2log{1+x/1-x}
which is equal to f(x)
hence 2f(x)
as if you put the value of x in f(x)
then in the bracket you will get
1+x^2+2x/1+x^2-2x
as both numerator and denominator form the formula of (a+b)^2 & (a-b)^2
therefore it will be
log{(1+x)^2/(1-x)^2}
log{1+x/1-x}^2
as it is the property of log that the power comes down therefore it will be equal to
2log{1+x/1-x}
which is equal to f(x)
hence 2f(x)
sriram77:
ur welcome
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